Nuprl Lemma : module_plus_assoc
∀[A:Rng]. ∀[m:A-Module]. ∀[x,y,z:m.car]. ((x m.plus (y m.plus z)) = ((x m.plus y) m.plus z) ∈ m.car)
Proof
Definitions occuring in Statement :
module: A-Module,
alg_plus: a.plus,
alg_car: a.car,
uall: ∀[x:A]. B[x],
infix_ap: x f y,
equal: s = t ∈ T,
rng: Rng
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
all: ∀x:A. B[x],
rng: Rng,
and: P ∧ Q,
module: A-Module,
guard: {T},
group_p: IsGroup(T;op;id;inv),
monoid_p: IsMonoid(T;op;id),
assoc: Assoc(T;op)
Lemmas referenced :
module_properties,
alg_car_wf,
rng_car_wf,
module_wf,
rng_wf
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
lemma_by_obid,
sqequalHypSubstitution,
dependent_functionElimination,
thin,
setElimination,
rename,
hypothesisEquality,
hypothesis,
productElimination,
isectElimination,
sqequalRule,
isect_memberEquality,
axiomEquality,
because_Cache
Latex:
\mforall{}[A:Rng]. \mforall{}[m:A-Module]. \mforall{}[x,y,z:m.car]. ((x m.plus (y m.plus z)) = ((x m.plus y) m.plus z))
Date html generated:
2016_05_16-AM-07_26_31
Last ObjectModification:
2015_12_28-PM-05_08_18
Theory : algebras_1
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