Nuprl Lemma : fo-logic-test2
∀x:Dom. ((B x) ⇒ (B x))
Proof
Definitions occuring in Statement :
language1: language1{i:l}(D,A,B,C,P,Q,R,H.fml[D;A;B;C;P;Q;R;H]),
all: ∀x:A. B[x],
implies: P ⇒ Q,
apply: f a
\mforall{}x:Dom. ((B x) {}\mRightarrow{} (B x))
Date html generated:
2015_07_17-AM-07_52_45
Last ObjectModification:
2015_01_30-AM-01_13_09
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