Nuprl Lemma : halfpi-half-pi

π/2 = π/2(slower)


Proof




Definitions occuring in Statement :  halfpi: π/2 half-pi: π/2(slower) req: y
Definitions unfolded in proof :  member: t ∈ T squash: T uall: [x:A]. B[x] sq_stable: SqStable(P) implies:  Q
Lemmas referenced :  halfpi_wf1 sq_stable__req half-pi_wf
Rules used in proof :  cut introduction extract_by_obid sqequalHypSubstitution sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity Error :applyLambdaEquality,  setElimination thin rename hypothesis sqequalRule imageMemberEquality hypothesisEquality baseClosed imageElimination isectElimination equalityTransitivity equalitySymmetry independent_functionElimination

Latex:
\mpi{}/2  =  \mpi{}/2(slower)



Date html generated: 2016_10_26-PM-00_23_00
Last ObjectModification: 2016_09_12-PM-05_42_44

Theory : reals_2


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