Nuprl Lemma : example2

x.(B x)  (C x)  ∃z.B  ∃y.C y


Proof




Definitions occuring in Statement :  language1: language1{i:l}(D,A,B,C,P,Q,R,H.fml[D;A;B;C;P;Q;R;H]) forsome: x.P[x] forall: x.P[x] implies:  Q apply: a
Definitions unfolded in proof :  language1: language1{i:l}(D,A,B,C,P,Q,R,H.fml[D;A;B;C;P;Q;R;H]) uall: [x:A]. B[x] !hyp_hide: x member: t ∈ T prop: implies:  Q so_lambda: λ2x.t[x] so_apply: x[s] forsome: x.P[x] exists: x:A. B[x] forall: x.P[x] all: x:A. B[x]
Lemmas referenced :  forsome_wf forall_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation sqequalHypSubstitution functionEquality cumulativity hypothesisEquality universeEquality because_Cache lambdaFormation cut lemma_by_obid isectElimination thin sqequalRule lambdaEquality applyEquality hypothesis productElimination dependent_pairFormation addLevel dependent_functionElimination levelHypothesis independent_functionElimination

Latex:
\mforall{}x.(B  x)  {}\mRightarrow{}  (C  x)  {}\mRightarrow{}  \mexists{}z.B  z  {}\mRightarrow{}  \mexists{}y.C  y



Date html generated: 2016_05_16-AM-09_07_59
Last ObjectModification: 2015_12_28-PM-07_02_57

Theory : first-order!and!ancestral!logic


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