Nuprl Lemma : add_com
∀[a,b:ℤ]. ((a + b) = (b + a) ∈ ℤ)
Proof
Definitions occuring in Statement :
uall: ∀[x:A]. B[x],
add: n + m,
int: ℤ,
equal: s = t ∈ T
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
subtype_rel: A ⊆r B,
top: Top
Lemmas referenced :
add-commutes
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
sqequalRule,
lemma_by_obid,
sqequalHypSubstitution,
isectElimination,
thin,
hypothesisEquality,
applyEquality,
lambdaEquality,
isect_memberEquality,
voidElimination,
voidEquality,
intEquality,
hypothesis,
addEquality,
axiomEquality,
because_Cache
Latex:
\mforall{}[a,b:\mBbbZ{}]. ((a + b) = (b + a))
Date html generated:
2016_05_13-PM-03_39_35
Last ObjectModification:
2015_12_26-AM-09_40_43
Theory : arithmetic
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