Nuprl Lemma : has-valueall-lambda
∀[a:Base]. has-valueall(λx.a[x])
Proof
Definitions occuring in Statement :
has-valueall: has-valueall(a),
uall: ∀[x:A]. B[x],
so_apply: x[s],
lambda: λx.A[x],
base: Base
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
has-valueall: has-valueall(a),
evalall: evalall(t),
has-value: (a)↓
Lemmas referenced :
base_wf,
is-exception_wf,
has-value_wf_base
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
sqequalRule,
divergentSqle,
sqleReflexivity,
lemma_by_obid,
sqequalHypSubstitution,
isectElimination,
thin,
baseClosed,
hypothesis,
axiomSqleEquality
Latex:
\mforall{}[a:Base]. has-valueall(\mlambda{}x.a[x])
Date html generated:
2016_05_13-PM-03_25_34
Last ObjectModification:
2016_01_14-PM-06_44_21
Theory : call!by!value_1
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