Nuprl Lemma : symmetrize_wf
∀[T:𝕌{j}]. ∀[R:T ⟶ T ⟶ ℙ]. ∀[a,b:T]. (Symmetrize(x,y.R[x;y];a;b) ∈ ℙ)
Proof
Definitions occuring in Statement :
symmetrize: Symmetrize(x,y.R[x; y];a;b),
uall: ∀[x:A]. B[x],
prop: ℙ,
so_apply: x[s1;s2],
member: t ∈ T,
function: x:A ⟶ B[x],
universe: Type
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
symmetrize: Symmetrize(x,y.R[x; y];a;b),
prop: ℙ,
and: P ∧ Q,
so_apply: x[s1;s2],
subtype_rel: A ⊆r B
Lemmas referenced :
subtype_rel_self
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
Error :isect_memberFormation_alt,
introduction,
cut,
sqequalRule,
productEquality,
applyEquality,
hypothesisEquality,
hypothesis,
thin,
instantiate,
extract_by_obid,
sqequalHypSubstitution,
isectElimination,
universeEquality,
because_Cache,
axiomEquality,
equalityTransitivity,
equalitySymmetry,
Error :inhabitedIsType,
isect_memberEquality,
Error :universeIsType,
Error :functionIsType,
functionEquality,
cumulativity
Latex:
\mforall{}[T:\mBbbU{}\{j\}]. \mforall{}[R:T {}\mrightarrow{} T {}\mrightarrow{} \mBbbP{}]. \mforall{}[a,b:T]. (Symmetrize(x,y.R[x;y];a;b) \mmember{} \mBbbP{})
Date html generated:
2019_06_20-PM-00_28_56
Last ObjectModification:
2018_09_26-AM-11_46_39
Theory : rel_1
Home
Index