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Logical Investigations, with the Nuprl Proof Assistant
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Theorem 6: (P ⇒ Q) ⇒ (∼Q ⇒ ∼P)


∀[P,Q:ℙ].((P ⇒ Q) ⇒ (¬Q) ⇒ (¬P)) Extract: λpq,nq,p.(nq (pq p)) where pq : P ⇒ Q nq : ¬Q ≡ (Q ⇒ False) p : P

This theorem is known as the contrapositive claim. It says that if we know some proposition P implies the proposition Q, then we also know that ∼Q implies ∼P. Using the contrapositive of a statement can be a useful method for proving theorems. The contrapositive claim actually has the same shape as Theorem 3, which states that (A ⇒ B) ⇒ ((B ⇒ C) ⇒ (A ⇒ C)), for propositions A, B, and C. The two theorems are the same when you replace A, B, and C with P, Q, and False, respectively.


Nuprl Proof


⊢ ∀[P,Q:ℙ]. ((P ⇒ Q) ⇒ (¬Q) ⇒ (¬P)) | BY RepeatFor 2 ((UD THENA Auto)) | [1]. P: ℙ [2]. Q: ℙ ⊢ (P ⇒ Q) ⇒ (¬Q) ⇒ (¬P) | BY RepeatFor 2 ((D 0 THENA Auto)) Construction rule, 2 times | 3. P ⇒ Q 4. ¬Q ⊢ ¬P | BY Unfold `not` 0 | ⊢ P ⇒ False Definition of negation | BY (D 0 THENA Auto) Construction rule | 5. P ⊢ False | BY Unfold `not` 4 | 4. Q ⇒ False Definition of negation ⊢ False | BY D 3 Application rule on (P ⇒ Q) |\ | 3. Q ⇒ False | 4. P | ⊢ P Subgoal 1: Prove P | | 1 BY NthHyp 4 Hypothesis rule \ 3. Q ⇒ False 4. P 5. Q ⊢ False Subgoal 2: Show False, with evidence for Q now available | BY D 3 Application rule on (Q ⇒ False) |\ | 3. P | 4. Q | ⊢ Q Subgoal 2.1: Prove Q | | 1 BY NthHyp 4 Hypothesis rule \ 3. P 4. Q 5. False ⊢ False Subgoal 2.2: Show False, with the False assumption now available | BY NthHyp 5 Hypothesis rule




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