Logical Investigations, with the Nuprl Proof Assistant
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Theorem 6: (P ⇒ Q) ⇒ (∼Q ⇒ ∼P)
∀[P,Q:ℙ].((P ⇒ Q) ⇒ (¬Q) ⇒ (¬P))
Extract: λpq,nq,p.(nq (pq p))
    where pq : P ⇒ Q
          nq : ¬Q ≡ (Q ⇒ False)
           p : P
This theorem is known as the contrapositive claim. It says that if we know some proposition P implies the proposition Q, then we also know that ∼Q implies ∼P. Using the contrapositive of a statement can be a useful method for proving theorems. The contrapositive claim actually has the same shape as Theorem 3, which states that (A ⇒ B) ⇒ ((B ⇒ C) ⇒ (A ⇒ C)), for propositions A, B, and C. The two theorems are the same when you replace A, B, and C with P, Q, and False, respectively.
Nuprl Proof
⊢ ∀[P,Q:ℙ].  ((P ⇒ Q) ⇒ (¬Q) ⇒ (¬P))
|
BY RepeatFor 2 ((UD THENA Auto))
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[1]. P: ℙ
[2]. Q: ℙ
⊢ (P ⇒ Q) ⇒ (¬Q) ⇒ (¬P)
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BY RepeatFor 2 ((D 0 THENA Auto))     Construction rule, 2 times
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3. P ⇒ Q
4. ¬Q
⊢ ¬P
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BY Unfold `not` 0
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⊢ P ⇒ False    Definition of negation
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BY (D 0 THENA Auto)     Construction rule
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5. P
⊢ False
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BY Unfold `not` 4
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4. Q ⇒ False    Definition of negation
⊢ False
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BY D 3     Application rule on (P ⇒ Q)
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| 3. Q ⇒ False
| 4. P
| ⊢ P     Subgoal 1: Prove P
| |
1 BY NthHyp 4    Hypothesis rule
 \  
  3. Q ⇒ False
  4. P
  5. Q
  ⊢ False     Subgoal 2: Show False, with evidence for Q now available
  |
  BY D 3       Application rule on (Q ⇒ False)
  |\
  | 3. P
  | 4. Q
  | ⊢ Q      Subgoal 2.1: Prove Q
  | |
  1 BY NthHyp 4     Hypothesis rule
   \
    3. P
    4. Q
    5. False
    ⊢ False   Subgoal 2.2: Show False, with the False assumption now available
    |
    BY NthHyp 5    Hypothesis rule
    
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