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RankTheoremName
6 Thm* n:, a,b:. sum(a+bi | i < n) = ((n(a+a+b(n-1))) 2)[sum_arith]
cites
0 Thm* n:, a,b:. sum(a+bi | i < n)2 = n(a+a+b(n-1))[sum_arith1]
3 Thm* a,b:, n:. na = nb a = b[mul_cancel_in_eq]
0 Thm* a:, n:. a = (a n)n+(a rem n)[div_rem_sum]
3 Thm* a,b:, n:. ((a+bn) rem n) = (a rem n)[rem_invariant]
5 Thm* a:{...0}, n:. (a rem n) = -((-a) rem n)[rem_2_to_1]

graph 1 1 Sections Graphs Doc