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lambda
jlc
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No mentions to report in lambda_jlc
applicative_Y
Def Y
(f) == (
x.f(
y.x(x,y)))(
x.f(
y.x(x,y)))
Syntax:
Y
has structure:
applicative_Y
About:
Definitions
lambda
jlc
Sections
Support(jlc)
Doc