Nuprl Lemma : bpa-equiv-iff-norm

∀p:{2...}. ∀x,y:basic-padic(p).  (bpa-equiv(p;x;y) ⇐⇒ bpa-norm(p;x) = bpa-norm(p;y) ∈ basic-padic(p))


Proof

Error : references
Latex:
\mforall{}p:\{2...\}.  \mforall{}x,y:basic-padic(p).    (bpa-equiv(p;x;y)  \mLeftarrow{}{}\mRightarrow{}  bpa-norm(p;x)  =  bpa-norm(p;y))


Date html generated: 2020_05_19-PM-10_08_51
Last ObjectModification: 2020_01_08-PM-06_38_13

Theory : rings_1


Home Index