Nuprl Lemma : bpa-equiv-iff-norm
∀p:{2...}. ∀x,y:basic-padic(p).  (bpa-equiv(p;x;y) 
⇐⇒ bpa-norm(p;x) = bpa-norm(p;y) ∈ basic-padic(p))
Proof
Error : references
Latex:
\mforall{}p:\{2...\}.  \mforall{}x,y:basic-padic(p).    (bpa-equiv(p;x;y)  \mLeftarrow{}{}\mRightarrow{}  bpa-norm(p;x)  =  bpa-norm(p;y))
Date html generated:
2020_05_19-PM-10_08_51
Last ObjectModification:
2020_01_08-PM-06_38_13
Theory : rings_1
Home
Index