Nuprl Lemma : decidable__pa-is-new-and

a:ProtocolAction. ∀P:Atom1 ⟶ ℙ.  ((∀v:Atom1. Dec(P[v]))  Dec(pa-is-new-and(a;v.P[v])))


Proof




Definitions occuring in Statement :  pa-is-new-and: pa-is-new-and(a;v.P[v]) protocol-action: ProtocolAction atom: Atom$n decidable: Dec(P) prop: so_apply: x[s] all: x:A. B[x] implies:  Q function: x:A ⟶ B[x]
Definitions unfolded in proof :  all: x:A. B[x] implies:  Q pa-is-new-and: pa-is-new-and(a;v.P[v]) protocol-action: ProtocolAction pi1: fst(t) pi2: snd(t) member: t ∈ T decidable: Dec(P) or: P ∨ Q uall: [x:A]. B[x] uimplies: supposing a sq_type: SQType(T) guard: {T} eq_atom: =a y ifthenelse: if then else fi  btrue: tt so_apply: x[s] prop: and: P ∧ Q cand: c∧ B not: ¬A false: False subtype_rel: A ⊆B so_lambda: λ2x.t[x]

Latex:
\mforall{}a:ProtocolAction.  \mforall{}P:Atom1  {}\mrightarrow{}  \mBbbP{}.    ((\mforall{}v:Atom1.  Dec(P[v]))  {}\mRightarrow{}  Dec(pa-is-new-and(a;v.P[v])))



Date html generated: 2016_05_17-PM-00_37_28
Last ObjectModification: 2016_01_18-AM-07_41_50

Theory : event-logic-applications


Home Index