Nuprl Lemma : rank-option

[P,Q:pi_term()].  (pi-rank(pioption(P;Q)) ((pi-rank(P) pi-rank(Q)) 1) ∈ ℕ)


Proof




Definitions occuring in Statement :  pi-rank: pi-rank(p) pioption: pioption(left;right) pi_term: pi_term() nat: uall: [x:A]. B[x] add: m natural_number: $n equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T pi-rank: pi-rank(p) pioption: pioption(left;right) pi_term_ind: pi_term_ind(v;zero;pre,body,rec1....;left,right,rec2,rec3....;left,right,rec4,rec5....;body,rec6....;name,body,rec7....) all: x:A. B[x] subtype_rel: A ⊆B nat: decidable: Dec(P) or: P ∨ Q uimplies: supposing a satisfiable_int_formula: satisfiable_int_formula(fmla) exists: x:A. B[x] false: False implies:  Q not: ¬A top: Top prop: le: A ≤ B and: P ∧ Q less_than': less_than'(a;b) guard: {T} ge: i ≥  uiff: uiff(P;Q)

Latex:
\mforall{}[P,Q:pi\_term()].    (pi-rank(pioption(P;Q))  =  ((pi-rank(P)  +  pi-rank(Q))  +  1))



Date html generated: 2016_05_17-AM-11_23_47
Last ObjectModification: 2016_01_18-AM-07_48_34

Theory : event-logic-applications


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