Nuprl Lemma : E-interface-pair

[Info:Type]. ∀[es:EO+(Info)]. ∀[X,Y:EClass(Top)].  E((X,Y)) E(Y) ∈ Type supposing E(Y) ⊆E(X)


Proof




Definitions occuring in Statement :  es-interface-pair: (X,Y) es-E-interface: E(X) eclass: EClass(A[eo; e]) event-ordering+: EO+(Info) uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] top: Top universe: Type equal: t ∈ T
Definitions unfolded in proof :  not: ¬A false: False assert: b bnot: ¬bb guard: {T} sq_type: SQType(T) or: P ∨ Q exists: x:A. B[x] bfalse: ff prop: ifthenelse: if then else fi  band: p ∧b q and: P ∧ Q uiff: uiff(P;Q) btrue: tt it: unit: Unit bool: 𝔹 implies:  Q all: x:A. B[x] subtype_rel: A ⊆B es-E-interface: E(X) uimplies: supposing a member: t ∈ T uall: [x:A]. B[x] true: True

Latex:
\mforall{}[Info:Type].  \mforall{}[es:EO+(Info)].  \mforall{}[X,Y:EClass(Top)].    E((X,Y))  =  E(Y)  supposing  E(Y)  \msubseteq{}r  E(X)



Date html generated: 2016_05_17-AM-08_10_57
Last ObjectModification: 2015_12_28-PM-11_11_57

Theory : event-ordering


Home Index