Nuprl Lemma : assert-fpf-is-empty

[A:Type]. ∀[B:A ⟶ Type]. ∀[f:x:A fp-> B[x]].  uiff(↑fpf-is-empty(f);f = ⊗ ∈ x:A fp-> B[x])


Proof




Definitions occuring in Statement :  fpf-is-empty: fpf-is-empty(f) fpf-empty: fpf: a:A fp-> B[a] assert: b uiff: uiff(P;Q) uall: [x:A]. B[x] so_apply: x[s] function: x:A ⟶ B[x] universe: Type equal: t ∈ T
Definitions unfolded in proof :  fpf: a:A fp-> B[a] fpf-is-empty: fpf-is-empty(f) pi1: fst(t) fpf-empty: member: t ∈ T uall: [x:A]. B[x] uiff: uiff(P;Q) and: P ∧ Q rev_uimplies: rev_uimplies(P;Q) uimplies: supposing a prop: so_apply: x[s] subtype_rel: A ⊆B so_lambda: λ2x.t[x] all: x:A. B[x] top: Top guard: {T} iff: ⇐⇒ Q rev_implies:  Q implies:  Q not: ¬A false: False

Latex:
\mforall{}[A:Type].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f:x:A  fp->  B[x]].    uiff(\muparrow{}fpf-is-empty(f);f  =  \motimes{})



Date html generated: 2016_05_16-AM-11_04_24
Last ObjectModification: 2015_12_29-AM-09_13_39

Theory : event-ordering


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