Nuprl Lemma : assert-has-src

[i:Id]. ∀[k:Knd].  uiff(↑has-src(i;k);(↑isrcv(k)) c∧ (source(lnk(k)) i ∈ Id))


Proof




Definitions occuring in Statement :  has-src: has-src(i;k) lsrc: source(l) lnk: lnk(k) isrcv: isrcv(k) Knd: Knd Id: Id assert: b uiff: uiff(P;Q) uall: [x:A]. B[x] cand: c∧ B equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a cand: c∧ B implies:  Q prop: Knd: Knd has-src: has-src(i;k) isrcv: isrcv(k) isl: isl(x) band: p ∧b q ifthenelse: if then else fi  btrue: tt assert: b true: True bfalse: ff false: False lnk: lnk(k) outl: outl(x) subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] all: x:A. B[x] top: Top rev_uimplies: rev_uimplies(P;Q)

Latex:
\mforall{}[i:Id].  \mforall{}[k:Knd].    uiff(\muparrow{}has-src(i;k);(\muparrow{}isrcv(k))  c\mwedge{}  (source(lnk(k))  =  i))



Date html generated: 2016_05_16-AM-10_59_58
Last ObjectModification: 2015_12_29-AM-09_10_27

Theory : event-ordering


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