Nuprl Lemma : eclass3-functional

[Info,B,C:Type]. ∀[X:EClass(B ⟶ C)]. ∀[Y:EClass(B)]. ∀[es:EO+(Info)].
  (eclass3(X;Y) is functional) supposing (X is functional and is functional)


Proof




Definitions occuring in Statement :  eclass3: eclass3(X;Y) es-functional-class: is functional eclass: EClass(A[eo; e]) event-ordering+: EO+(Info) uimplies: supposing a uall: [x:A]. B[x] function: x:A ⟶ B[x] universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a es-functional-class: is functional and: P ∧ Q single-valued-classrel: single-valued-classrel(es;X;T) all: x:A. B[x] implies:  Q prop: subtype_rel: A ⊆B es-total-class: es-total-class(es;X) le: A ≤ B not: ¬A false: False nat: so_lambda: λ2y.t[x; y] so_apply: x[s1;s2]

Latex:
\mforall{}[Info,B,C:Type].  \mforall{}[X:EClass(B  {}\mrightarrow{}  C)].  \mforall{}[Y:EClass(B)].  \mforall{}[es:EO+(Info)].
    (eclass3(X;Y)  is  functional)  supposing  (X  is  functional  and  Y  is  functional)



Date html generated: 2016_05_16-PM-02_13_59
Last ObjectModification: 2015_12_29-AM-11_47_18

Theory : event-ordering


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