Nuprl Lemma : es-interface-predecessors-equal-subtype

[Info:Type]. ∀[es:EO+(Info)]. ∀[X,Y:EClass(Top)].
  ∀[e:E]. (≤(X)(e) = ≤(Y)(e) ∈ ({e':E(X)| loc(e') loc(e) ∈ Id}  List)) supposing ∀e:E. (↑e ∈b ⇐⇒ ↑e ∈b Y)


Proof




Definitions occuring in Statement :  es-interface-predecessors: (X)(e) es-E-interface: E(X) in-eclass: e ∈b X eclass: EClass(A[eo; e]) event-ordering+: EO+(Info) es-loc: loc(e) es-E: E Id: Id list: List assert: b uimplies: supposing a uall: [x:A]. B[x] top: Top all: x:A. B[x] iff: ⇐⇒ Q set: {x:A| B[x]}  universe: Type equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a subtype_rel: A ⊆B es-E-interface: E(X) so_lambda: λ2x.t[x] so_apply: x[s] iff: ⇐⇒ Q all: x:A. B[x] rev_implies:  Q implies:  Q and: P ∧ Q prop: so_lambda: λ2y.t[x; y] so_apply: x[s1;s2]

Latex:
\mforall{}[Info:Type].  \mforall{}[es:EO+(Info)].  \mforall{}[X,Y:EClass(Top)].
    \mforall{}[e:E].  (\mleq{}(X)(e)  =  \mleq{}(Y)(e))  supposing  \mforall{}e:E.  (\muparrow{}e  \mmember{}\msubb{}  X  \mLeftarrow{}{}\mRightarrow{}  \muparrow{}e  \mmember{}\msubb{}  Y)



Date html generated: 2016_05_17-AM-06_55_05
Last ObjectModification: 2015_12_29-AM-00_16_22

Theory : event-ordering


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