Nuprl Lemma : fpf-cap-compatible
∀[X:Type]. ∀[eq:EqDecider(X)]. ∀[f,g:x:X fp-> Type]. ∀[x:X].
(f(x)?Void = g(x)?Void ∈ Type) supposing (g(x)?Void and f(x)?Void and f || g)
Proof
Definitions occuring in Statement :
fpf-compatible: f || g,
fpf-cap: f(x)?z,
fpf: a:A fp-> B[a],
deq: EqDecider(T),
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
void: Void,
universe: Type,
equal: s = t ∈ T
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
prop: ℙ,
so_lambda: λ2x.t[x],
so_apply: x[s],
subtype_rel: A ⊆r B,
all: ∀x:A. B[x],
top: Top,
fpf-compatible: f || g,
implies: P ⇒ Q,
and: P ∧ Q,
cand: A c∧ B,
bool: 𝔹,
unit: Unit,
it: ⋅,
btrue: tt,
uiff: uiff(P;Q),
ifthenelse: if b then t else f fi ,
bfalse: ff,
fpf-cap: f(x)?z
Latex:
\mforall{}[X:Type]. \mforall{}[eq:EqDecider(X)]. \mforall{}[f,g:x:X fp-> Type]. \mforall{}[x:X].
(f(x)?Void = g(x)?Void) supposing (g(x)?Void and f(x)?Void and f || g)
Date html generated:
2016_05_16-AM-11_09_15
Last ObjectModification:
2015_12_29-AM-09_16_55
Theory : event-ordering
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