Nuprl Lemma : fpf-cap-join-subtype

[A:Type]. ∀[eq:EqDecider(A)]. ∀[f,g:a:A fp-> Type]. ∀[a:A].  (f ⊕ g(a)?Top ⊆f(a)?Top)


Proof




Definitions occuring in Statement :  fpf-join: f ⊕ g fpf-cap: f(x)?z fpf: a:A fp-> B[a] deq: EqDecider(T) subtype_rel: A ⊆B uall: [x:A]. B[x] top: Top universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a all: x:A. B[x] top: Top fpf-cap: f(x)?z implies:  Q bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) and: P ∧ Q ifthenelse: if then else fi  bfalse: ff exists: x:A. B[x] prop: or: P ∨ Q sq_type: SQType(T) guard: {T} bnot: ¬bb assert: b false: False

Latex:
\mforall{}[A:Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[f,g:a:A  fp->  Type].  \mforall{}[a:A].    (f  \moplus{}  g(a)?Top  \msubseteq{}r  f(a)?Top)



Date html generated: 2016_05_16-AM-11_31_11
Last ObjectModification: 2015_12_29-AM-09_26_53

Theory : event-ordering


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