Nuprl Lemma : fpf-cap-subtype_functionality_wrt_sub2
∀[A1,A2,A3:Type]. ∀[d,d':EqDecider(A3)]. ∀[d2:EqDecider(A2)]. ∀[f:a:A1 fp-> Type]. ∀[g:a:A2 fp-> Type]. ∀[x:A3].
({g(x)?Top ⊆r f(x)?Top supposing f ⊆ g}) supposing (strong-subtype(A2;A3) and strong-subtype(A1;A2))
Proof
Definitions occuring in Statement :
fpf-sub: f ⊆ g,
fpf-cap: f(x)?z,
fpf: a:A fp-> B[a],
deq: EqDecider(T),
strong-subtype: strong-subtype(A;B),
uimplies: b supposing a,
subtype_rel: A ⊆r B,
uall: ∀[x:A]. B[x],
top: Top,
guard: {T},
universe: Type
Definitions unfolded in proof :
guard: {T},
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
subtype_rel: A ⊆r B,
prop: ℙ,
so_lambda: λ2x.t[x],
so_apply: x[s],
all: ∀x:A. B[x],
top: Top,
decidable: Dec(P),
or: P ∨ Q,
fpf-sub: f ⊆ g,
implies: P ⇒ Q,
strong-subtype: strong-subtype(A;B),
cand: A c∧ B,
fpf-ap: f(x),
pi2: snd(t),
fpf-cap: f(x)?z,
bool: 𝔹,
unit: Unit,
it: ⋅,
btrue: tt,
uiff: uiff(P;Q),
and: P ∧ Q,
ifthenelse: if b then t else f fi ,
bfalse: ff,
not: ¬A,
false: False
Latex:
\mforall{}[A1,A2,A3:Type]. \mforall{}[d,d':EqDecider(A3)]. \mforall{}[d2:EqDecider(A2)]. \mforall{}[f:a:A1 fp-> Type].
\mforall{}[g:a:A2 fp-> Type]. \mforall{}[x:A3].
(\{g(x)?Top \msubseteq{}r f(x)?Top supposing f \msubseteq{} g\}) supposing
(strong-subtype(A2;A3) and
strong-subtype(A1;A2))
Date html generated:
2016_05_16-AM-11_08_13
Last ObjectModification:
2015_12_29-AM-09_16_36
Theory : event-ordering
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