Nuprl Lemma : fpf-cap_functionality

[A:Type]. ∀[d1,d2:EqDecider(A)]. ∀[B:A ⟶ Type]. ∀[f:a:A fp-> B[a]]. ∀[x:A]. ∀[z:B[x]].  (f(x)?z f(x)?z ∈ B[x])


Proof




Definitions occuring in Statement :  fpf-cap: f(x)?z fpf: a:A fp-> B[a] deq: EqDecider(T) uall: [x:A]. B[x] so_apply: x[s] function: x:A ⟶ B[x] universe: Type equal: t ∈ T
Definitions unfolded in proof :  member: t ∈ T uall: [x:A]. B[x] subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a all: x:A. B[x] top: Top fpf-ap: f(x) pi2: snd(t) fpf: a:A fp-> B[a] fpf-dom: x ∈ dom(f) pi1: fst(t) not: ¬A implies:  Q iff: ⇐⇒ Q and: P ∧ Q rev_implies:  Q prop: false: False fpf-cap: f(x)?z bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) ifthenelse: if then else fi  bfalse: ff

Latex:
\mforall{}[A:Type].  \mforall{}[d1,d2:EqDecider(A)].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f:a:A  fp->  B[a]].  \mforall{}[x:A].  \mforall{}[z:B[x]].
    (f(x)?z  =  f(x)?z)



Date html generated: 2016_05_16-AM-11_07_47
Last ObjectModification: 2015_12_29-AM-09_15_42

Theory : event-ordering


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