Nuprl Lemma : fpf-dom-type
∀[X,Y:Type]. ∀[eq:EqDecider(Y)]. ∀[f:x:X fp-> Top]. ∀[x:Y]. (x ∈ X) supposing ((↑x ∈ dom(f)) and strong-subtype(X;Y))
Proof
Definitions occuring in Statement :
fpf-dom: x ∈ dom(f),
fpf: a:A fp-> B[a],
deq: EqDecider(T),
strong-subtype: strong-subtype(A;B),
assert: ↑b,
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
top: Top,
member: t ∈ T,
universe: Type
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
all: ∀x:A. B[x],
subtype_rel: A ⊆r B,
iff: P ⇐⇒ Q,
and: P ∧ Q,
implies: P ⇒ Q,
prop: ℙ,
so_lambda: λ2x.t[x],
so_apply: x[s]
Latex:
\mforall{}[X,Y:Type]. \mforall{}[eq:EqDecider(Y)]. \mforall{}[f:x:X fp-> Top]. \mforall{}[x:Y].
(x \mmember{} X) supposing ((\muparrow{}x \mmember{} dom(f)) and strong-subtype(X;Y))
Date html generated:
2016_05_16-AM-11_04_02
Last ObjectModification:
2015_12_29-AM-09_13_33
Theory : event-ordering
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