Nuprl Lemma : fpf-empty-join

[A:Type]. ∀[B:A ⟶ Type]. ∀[f:a:A fp-> B[a]]. ∀[eq:EqDecider(A)].  (f ⊕ ⊗ f ∈ a:A fp-> B[a])


Proof




Definitions occuring in Statement :  fpf-join: f ⊕ g fpf-empty: fpf: a:A fp-> B[a] deq: EqDecider(T) uall: [x:A]. B[x] so_apply: x[s] function: x:A ⟶ B[x] universe: Type equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T fpf: a:A fp-> B[a] fpf-empty: fpf-join: f ⊕ g pi1: fst(t) all: x:A. B[x] top: Top fpf-cap: f(x)?z fpf-dom: x ∈ dom(f) subtype_rel: A ⊆B uimplies: supposing a prop: so_apply: x[s] so_lambda: λ2x.t[x] not: ¬A implies:  Q false: False bool: 𝔹 unit: Unit it: btrue: tt iff: ⇐⇒ Q and: P ∧ Q rev_implies:  Q ifthenelse: if then else fi  bfalse: ff

Latex:
\mforall{}[A:Type].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[f:a:A  fp->  B[a]].  \mforall{}[eq:EqDecider(A)].    (f  \moplus{}  \motimes{}  =  f)



Date html generated: 2016_05_16-AM-11_09_43
Last ObjectModification: 2015_12_29-AM-09_22_33

Theory : event-ordering


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