Nuprl Lemma : fpf-join-range

[A:Type]. ∀[eq:EqDecider(A)]. ∀[df:x:A fp-> Type]. ∀[f:x:A fp-> df(x)?Top]. ∀[dg:x:A fp-> Type].
[g:x:A fp-> dg(x)?Top].
  (f ⊕ g ∈ x:A fp-> df ⊕ dg(x)?Top) supposing 
     ((∀x:A. ((↑x ∈ dom(g))  (↑x ∈ dom(dg)))) and 
     (∀x:A. ((↑x ∈ dom(f))  (↑x ∈ dom(df)))) and 
     df || dg)


Proof




Definitions occuring in Statement :  fpf-join: f ⊕ g fpf-compatible: || g fpf-cap: f(x)?z fpf-dom: x ∈ dom(f) fpf: a:A fp-> B[a] deq: EqDecider(T) assert: b uimplies: supposing a uall: [x:A]. B[x] top: Top all: x:A. B[x] implies:  Q member: t ∈ T universe: Type
Definitions unfolded in proof :  member: t ∈ T uall: [x:A]. B[x] so_lambda: λ2x.t[x] implies:  Q prop: subtype_rel: A ⊆B so_apply: x[s] uimplies: supposing a all: x:A. B[x] top: Top fpf-join: f ⊕ g fpf: a:A fp-> B[a] fpf-dom: x ∈ dom(f) pi1: fst(t) fpf-cap: f(x)?z bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) and: P ∧ Q ifthenelse: if then else fi  bfalse: ff exists: x:A. B[x] or: P ∨ Q sq_type: SQType(T) guard: {T} bnot: ¬bb assert: b false: False iff: ⇐⇒ Q not: ¬A rev_implies:  Q squash: T true: True fpf-compatible: || g cand: c∧ B

Latex:
\mforall{}[A:Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[df:x:A  fp->  Type].  \mforall{}[f:x:A  fp->  df(x)?Top].  \mforall{}[dg:x:A  fp->  Type].
\mforall{}[g:x:A  fp->  dg(x)?Top].
    (f  \moplus{}  g  \mmember{}  x:A  fp->  df  \moplus{}  dg(x)?Top)  supposing 
          ((\mforall{}x:A.  ((\muparrow{}x  \mmember{}  dom(g))  {}\mRightarrow{}  (\muparrow{}x  \mmember{}  dom(dg))))  and 
          (\mforall{}x:A.  ((\muparrow{}x  \mmember{}  dom(f))  {}\mRightarrow{}  (\muparrow{}x  \mmember{}  dom(df))))  and 
          df  ||  dg)



Date html generated: 2016_05_16-AM-11_11_36
Last ObjectModification: 2016_01_17-PM-03_49_44

Theory : event-ordering


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