Nuprl Lemma : fpf-sub_witness

[A:Type]. ∀[B:A ⟶ Type]. ∀[eq:EqDecider(A)]. ∀[f,g:a:A fp-> B[a]].  (f ⊆  x,y. <Ax, Ax> ∈ f ⊆ g))


Proof




Definitions occuring in Statement :  fpf-sub: f ⊆ g fpf: a:A fp-> B[a] deq: EqDecider(T) uall: [x:A]. B[x] so_apply: x[s] implies:  Q member: t ∈ T lambda: λx.A[x] function: x:A ⟶ B[x] pair: <a, b> universe: Type axiom: Ax
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T implies:  Q fpf-sub: f ⊆ g all: x:A. B[x] cand: c∧ B subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a top: Top prop: guard: {T}

Latex:
\mforall{}[A:Type].  \mforall{}[B:A  {}\mrightarrow{}  Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[f,g:a:A  fp->  B[a]].    (f  \msubseteq{}  g  {}\mRightarrow{}  (\mlambda{}x,y.  <Ax,  Ax>  \mmember{}  f  \000C\msubseteq{}  g))



Date html generated: 2016_05_16-AM-11_06_19
Last ObjectModification: 2015_12_29-AM-09_14_23

Theory : event-ordering


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