Nuprl Lemma : fpf-val-single1

[A:Type]. ∀[eq:EqDecider(A)]. ∀[x:A]. ∀[v,P:Top].  (z != v(x) ==> P[a;z] True  P[x;v])


Proof




Definitions occuring in Statement :  fpf-single: v fpf-val: != f(x) ==> P[a; z] deq: EqDecider(T) uall: [x:A]. B[x] top: Top so_apply: x[s1;s2] implies:  Q true: True universe: Type sqequal: t
Definitions unfolded in proof :  fpf-single: v fpf-val: != f(x) ==> P[a; z] all: x:A. B[x] member: t ∈ T top: Top fpf-dom: x ∈ dom(f) pi1: fst(t) deq: EqDecider(T) implies:  Q bool: 𝔹 unit: Unit it: btrue: tt uall: [x:A]. B[x] eqof: eqof(d) uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a bor: p ∨bq ifthenelse: if then else fi  assert: b bfalse: ff iff: ⇐⇒ Q not: ¬A prop: rev_implies:  Q false: False

Latex:
\mforall{}[A:Type].  \mforall{}[eq:EqDecider(A)].  \mforall{}[x:A].  \mforall{}[v,P:Top].    (z  !=  x  :  v(x)  ==>  P[a;z]  \msim{}  True  {}\mRightarrow{}  P[x;v])



Date html generated: 2016_05_16-AM-11_17_28
Last ObjectModification: 2015_12_29-AM-09_22_02

Theory : event-ordering


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