Nuprl Lemma : id-member-normal-form

[x,L:Top].  (rec-case(L) of [] => ff a::_ => r.if a=2 then tt else x ∈b L)


Proof




Definitions occuring in Statement :  id-deq: IdDeq deq-member: x ∈b L list_ind: list_ind atom_eq: atomeqn def bfalse: ff btrue: tt uall: [x:A]. B[x] top: Top sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T list_ind: list_ind btrue: tt it: bfalse: ff deq-member: x ∈b L reduce: reduce(f;k;as) bor: p ∨bq ifthenelse: if then else fi  id-deq: IdDeq atom2-deq: Atom2Deq eq_atom: eq_atom$n(x;y) so_lambda: so_lambda(x,y,z,w.t[x; y; z; w]) so_apply: x[s1;s2;s3;s4] so_lambda: λ2x.t[x] top: Top so_apply: x[s] uimplies: supposing a strict4: strict4(F) and: P ∧ Q all: x:A. B[x] implies:  Q has-value: (a)↓ prop: guard: {T} or: P ∨ Q squash: T

Latex:
\mforall{}[x,L:Top].    (rec-case(L)  of  []  =>  ff  |  a::$_{}$  =>  r.if  a=2  x  then  tt  else  r  \msim{}  \000Cx  \mmember{}\msubb{}  L)



Date html generated: 2016_05_16-AM-11_02_07
Last ObjectModification: 2016_01_17-PM-03_47_31

Theory : event-ordering


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