Nuprl Lemma : interface-union-val

[Info:Type]. ∀[es:EO+(Info)]. ∀[A,B:Type]. ∀[X:EClass(A)]. ∀[Y:EClass(B)]. ∀[e:E].
  X+Y(e) if e ∈b then inl X(e) else inr Y(e)  fi  ∈ (A B) supposing ↑e ∈b X+Y


Proof




Definitions occuring in Statement :  es-interface-union: X+Y eclass-val: X(e) in-eclass: e ∈b X eclass: EClass(A[eo; e]) event-ordering+: EO+(Info) es-E: E assert: b ifthenelse: if then else fi  uimplies: supposing a uall: [x:A]. B[x] inr: inr  inl: inl x union: left right universe: Type equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a eclass: EClass(A[eo; e]) eclass-val: X(e) in-eclass: e ∈b X es-interface-union: X+Y eclass-compose2: eclass-compose2(f;X;Y) subtype_rel: A ⊆B all: x:A. B[x] implies:  Q bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) and: P ∧ Q nat: ifthenelse: if then else fi  top: Top eq_int: (i =z j) assert: b cand: c∧ B decidable: Dec(P) or: P ∨ Q satisfiable_int_formula: satisfiable_int_formula(fmla) exists: x:A. B[x] false: False not: ¬A prop: bfalse: ff sq_type: SQType(T) guard: {T} bnot: ¬bb nequal: a ≠ b ∈  so_lambda: λ2y.t[x; y] so_apply: x[s1;s2]

Latex:
\mforall{}[Info:Type].  \mforall{}[es:EO+(Info)].  \mforall{}[A,B:Type].  \mforall{}[X:EClass(A)].  \mforall{}[Y:EClass(B)].  \mforall{}[e:E].
    X+Y(e)  =  if  e  \mmember{}\msubb{}  X  then  inl  X(e)  else  inr  Y(e)    fi    supposing  \muparrow{}e  \mmember{}\msubb{}  X+Y



Date html generated: 2016_05_16-PM-10_36_17
Last ObjectModification: 2016_01_17-PM-07_21_28

Theory : event-ordering


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