Nuprl Lemma : latest-pair_wf

[Info,A,B:Type]. ∀[X:EClass(A)]. ∀[Y:EClass(B)].  ((X&Y) ∈ EClass(A × B))


Proof




Definitions occuring in Statement :  latest-pair: (X&Y) eclass: EClass(A[eo; e]) uall: [x:A]. B[x] member: t ∈ T product: x:A × B[x] universe: Type
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T latest-pair: (X&Y) subtype_rel: A ⊆B all: x:A. B[x] implies:  Q bool: 𝔹 unit: Unit it: btrue: tt ifthenelse: if then else fi  uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a nat: cand: c∧ B decidable: Dec(P) or: P ∨ Q satisfiable_int_formula: satisfiable_int_formula(fmla) exists: x:A. B[x] false: False not: ¬A top: Top prop: bfalse: ff sq_type: SQType(T) guard: {T} bnot: ¬bb assert: b nequal: a ≠ b ∈  so_lambda: λ2y.t[x; y] so_apply: x[s1;s2]

Latex:
\mforall{}[Info,A,B:Type].  \mforall{}[X:EClass(A)].  \mforall{}[Y:EClass(B)].    ((X\&Y)  \mmember{}  EClass(A  \mtimes{}  B))



Date html generated: 2016_05_17-AM-07_14_01
Last ObjectModification: 2016_01_17-PM-03_01_42

Theory : event-ordering


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