Nuprl Lemma : lnk-decl-dom-implies
∀[k:Knd]. ∀[l:IdLnk]. ∀[dt:x:Id fp-> Type]. {(↑isrcv(k)) c∧ (↑tag(k) ∈ dom(dt))} supposing ↑k ∈ dom(lnk-decl(l;dt))
Proof
Definitions occuring in Statement :
lnk-decl: lnk-decl(l;dt),
fpf-dom: x ∈ dom(f),
fpf: a:A fp-> B[a],
Kind-deq: KindDeq,
tagof: tag(k),
isrcv: isrcv(k),
Knd: Knd,
IdLnk: IdLnk,
id-deq: IdDeq,
Id: Id,
assert: ↑b,
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
cand: A c∧ B,
guard: {T},
universe: Type
Definitions unfolded in proof :
Knd: Knd,
rcv: rcv(l,tg),
tagof: tag(k),
isrcv: isrcv(k),
isl: isl(x),
outl: outl(x),
assert: ↑b,
ifthenelse: if b then t else f fi ,
btrue: tt,
pi2: snd(t),
locl: locl(a),
bfalse: ff,
member: t ∈ T,
uall: ∀[x:A]. B[x],
subtype_rel: A ⊆r B,
so_lambda: λ2x.t[x],
so_apply: x[s],
uimplies: b supposing a,
all: ∀x:A. B[x],
top: Top,
prop: ℙ,
guard: {T},
cand: A c∧ B,
implies: P ⇒ Q,
IdLnk: IdLnk,
Id: Id,
sq_type: SQType(T),
true: True,
false: False
Latex:
\mforall{}[k:Knd]. \mforall{}[l:IdLnk]. \mforall{}[dt:x:Id fp-> Type].
\{(\muparrow{}isrcv(k)) c\mwedge{} (\muparrow{}tag(k) \mmember{} dom(dt))\} supposing \muparrow{}k \mmember{} dom(lnk-decl(l;dt))
Date html generated:
2016_05_16-AM-11_35_44
Last ObjectModification:
2015_12_29-AM-09_30_29
Theory : event-ordering
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