Nuprl Lemma : manames-overlap-case-symmetry
∀[x,y:Top]. ∀[nms1,nms2:MaName List].
(if nms1 and nms2 overlap then x else y fi ~ if nms2 and nms1 overlap then x else y fi)
Proof
Definitions occuring in Statement :
manames-overlap-case: if nms1 and nms2 overlap then x else y fi,
MaName: MaName,
list: T List,
uall: ∀[x:A]. B[x],
top: Top,
sqequal: s ~ t
Definitions unfolded in proof :
manames-overlap-case: if nms1 and nms2 overlap then x else y fi,
branch: if p:P then A[p] else B fi ,
member: t ∈ T,
subtype_rel: A ⊆r B,
all: ∀x:A. B[x],
uall: ∀[x:A]. B[x],
so_lambda: λ2x.t[x],
so_apply: x[s],
prop: ℙ,
implies: P ⇒ Q,
decidable: Dec(P),
or: P ∨ Q,
not: ¬A,
uiff: uiff(P;Q),
and: P ∧ Q,
uimplies: b supposing a,
false: False
Latex:
\mforall{}[x,y:Top]. \mforall{}[nms1,nms2:MaName List].
(if nms1 and nms2 overlap then x else y fi \msim{} if nms2 and nms1 overlap then x else y fi)
Date html generated:
2016_05_16-AM-11_01_52
Last ObjectModification:
2015_12_29-AM-09_11_31
Theory : event-ordering
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