Nuprl Lemma : outl-or-class

[Info,A,B:Type]. ∀[X:EClass(A)]. ∀[Y:EClass(B)].  (outl-class(or-class(X;Y)) X ∈ EClass(A))


Proof




Definitions occuring in Statement :  or-class: or-class(X;Y) outl-class: outl-class(X) eclass: EClass(A[eo; e]) uall: [x:A]. B[x] universe: Type equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T so_lambda: λ2y.t[x; y] subtype_rel: A ⊆B so_apply: x[s1;s2] uimplies: supposing a all: x:A. B[x] top: Top or-class: or-class(X;Y) outl-class: outl-class(X) inr-class: inr-class(X) inl-class: inl-class(X) parallel-class: || Y eclass-compose1: X eclass-compose2: eclass-compose2(f;X;Y) eclass: EClass(A[eo; e]) implies:  Q bag-mapfilter: bag-mapfilter(f;P;bs) bag-merge: bag-merge(as;bs) bag-separate: bag-separate(bs) pi1: fst(t)

Latex:
\mforall{}[Info,A,B:Type].  \mforall{}[X:EClass(A)].  \mforall{}[Y:EClass(B)].    (outl-class(or-class(X;Y))  =  X)



Date html generated: 2016_05_16-PM-10_39_13
Last ObjectModification: 2015_12_29-AM-10_55_36

Theory : event-ordering


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