Nuprl Lemma : ranked-eo-eq-E

[L,rk:Top]. ∀[a,b:Top × ℤ].  (a fst(a) fst(b) ∧b (snd(a) =z snd(b)))


Proof




Definitions occuring in Statement :  ranked-eo: ranked-eo(L;rk) es-eq-E: e' eq_id: b band: p ∧b q eq_int: (i =z j) uall: [x:A]. B[x] top: Top pi1: fst(t) pi2: snd(t) product: x:A × B[x] int: sqequal: t
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T es-eq-E: e' es-eq: es-eq(es) es-locless: es-locless(es;e1;e2) top: Top ranked-eo: ranked-eo(L;rk) mk-extended-eo: mk-extended-eo all: x:A. B[x] eq_atom: =a y ifthenelse: if then else fi  bfalse: ff mk-eo: mk-eo(E;dom;l;R;locless;pred;rank) mk-eo-record: mk-eo-record(E;dom;l;R;locless;pred;rank) btrue: tt infix_ap: y pi1: fst(t) pi2: snd(t) uimplies: supposing a iff: ⇐⇒ Q and: P ∧ Q implies:  Q decidable: Dec(P) or: P ∨ Q satisfiable_int_formula: satisfiable_int_formula(fmla) exists: x:A. B[x] false: False not: ¬A prop: rev_implies:  Q uiff: uiff(P;Q) sq_type: SQType(T) guard: {T}

Latex:
\mforall{}[L,rk:Top].  \mforall{}[a,b:Top  \mtimes{}  \mBbbZ{}].    (a  =  b  \msim{}  fst(a)  =  fst(b)  \mwedge{}\msubb{}  (snd(a)  =\msubz{}  snd(b)))



Date html generated: 2016_05_17-AM-08_43_37
Last ObjectModification: 2016_01_17-PM-02_28_53

Theory : event-ordering


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