Nuprl Lemma : subtype-fpf-cap

[X:Type]. ∀[eq:EqDecider(X)]. ∀[f,g:x:X fp-> Type].  {∀[x:X]. (f(x)?Top ⊆g(x)?Top)} supposing g ⊆ f


Proof




Definitions occuring in Statement :  fpf-sub: f ⊆ g fpf-cap: f(x)?z fpf: a:A fp-> B[a] deq: EqDecider(T) uimplies: supposing a subtype_rel: A ⊆B uall: [x:A]. B[x] top: Top guard: {T} universe: Type
Definitions unfolded in proof :  member: t ∈ T uall: [x:A]. B[x] subtype_rel: A ⊆B so_lambda: λ2x.t[x] so_apply: x[s] uimplies: supposing a all: x:A. B[x] top: Top fpf-sub: f ⊆ g implies:  Q cand: c∧ B not: ¬A false: False guard: {T} fpf-cap: f(x)?z bool: 𝔹 unit: Unit it: btrue: tt uiff: uiff(P;Q) and: P ∧ Q ifthenelse: if then else fi  bfalse: ff prop:

Latex:
\mforall{}[X:Type].  \mforall{}[eq:EqDecider(X)].  \mforall{}[f,g:x:X  fp->  Type].
    \{\mforall{}[x:X].  (f(x)?Top  \msubseteq{}r  g(x)?Top)\}  supposing  g  \msubseteq{}  f



Date html generated: 2016_05_16-AM-11_07_23
Last ObjectModification: 2015_12_29-AM-09_16_07

Theory : event-ordering


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