Nuprl Lemma : hdf-parallel-bind-eq-gen

[A,B1,B2,C:Type]. ∀[X1:hdataflow(A;B1)]. ∀[X2:hdataflow(A;B2)]. ∀[Y1:B1 ⟶ hdataflow(A;C)]. ∀[Y2:B2 ⟶ hdataflow(A;C)].
  (X1 >>Y1 || X2 >>Y2 X1 X2 >>= λb.case of inl(b1) => Y1 b1 inr(b2) => Y2 b2 ∈ hdataflow(A;C)) supposing 
     (valueall-type(C) and 
     valueall-type(B2) and 
     valueall-type(B1))


Proof




Definitions occuring in Statement :  hdf-bind: X >>Y hdf-union: Y hdf-parallel: || Y hdataflow: hdataflow(A;B) valueall-type: valueall-type(T) uimplies: supposing a uall: [x:A]. B[x] apply: a lambda: λx.A[x] function: x:A ⟶ B[x] decide: case of inl(x) => s[x] inr(y) => t[y] universe: Type equal: t ∈ T
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a eclass-disju-program: xpr ypr bind-class-program: xpr >>ypr parallel-class-program: || Y eclass1-program: eclass1-program(f;pr) mkid: "$x" Id: Id squash: T prop: implies:  Q guard: {T} iff: ⇐⇒ Q and: P ∧ Q rev_implies:  Q

Latex:
\mforall{}[A,B1,B2,C:Type].  \mforall{}[X1:hdataflow(A;B1)].  \mforall{}[X2:hdataflow(A;B2)].  \mforall{}[Y1:B1  {}\mrightarrow{}  hdataflow(A;C)].
\mforall{}[Y2:B2  {}\mrightarrow{}  hdataflow(A;C)].
    (X1  >>=  Y1  ||  X2  >>=  Y2  =  X1  +  X2  >>=  \mlambda{}b.case  b  of  inl(b1)  =>  Y1  b1  |  inr(b2)  =>  Y2  b2)  supposing 
          (valueall-type(C)  and 
          valueall-type(B2)  and 
          valueall-type(B1))



Date html generated: 2016_05_17-AM-09_12_25
Last ObjectModification: 2016_01_17-PM-09_12_23

Theory : local!classes


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