Nuprl Lemma : collect_filter_wf
∀[A:Type]. ∀[P:{L:A List| 0 < ||L||} ⟶ 𝔹].
(collect_filter() ∈ (ℤ × {L:A List| 0 < ||L|| ⇒ (¬↑P[L])} × ({L:A List| 0 < ||L|| ∧ (↑P[L])} + Top))
⟶ bag(ℤ × {L:A List| 0 < ||L|| ∧ (↑P[L])} ))
Proof
Definitions occuring in Statement :
collect_filter: collect_filter(),
length: ||as||,
list: T List,
assert: ↑b,
bool: 𝔹,
less_than: a < b,
uall: ∀[x:A]. B[x],
top: Top,
so_apply: x[s],
not: ¬A,
implies: P ⇒ Q,
and: P ∧ Q,
member: t ∈ T,
set: {x:A| B[x]} ,
function: x:A ⟶ B[x],
product: x:A × B[x],
union: left + right,
natural_number: $n,
int: ℤ,
universe: Type,
bag: bag(T)
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
collect_filter: collect_filter(),
spreadn: spread3,
all: ∀x:A. B[x],
and: P ∧ Q,
prop: ℙ,
so_apply: x[s],
implies: P ⇒ Q
Latex:
\mforall{}[A:Type]. \mforall{}[P:\{L:A List| 0 < ||L||\} {}\mrightarrow{} \mBbbB{}].
(collect\_filter() \mmember{} (\mBbbZ{}
\mtimes{} \{L:A List| 0 < ||L|| {}\mRightarrow{} (\mneg{}\muparrow{}P[L])\}
\mtimes{} (\{L:A List| 0 < ||L|| \mwedge{} (\muparrow{}P[L])\} + Top)) {}\mrightarrow{} bag(\mBbbZ{} \mtimes{} \{L:A List| 0 < ||L|| \mwedge{} (\muparrow{}P[L])\} ))
Date html generated:
2016_05_16-AM-10_10_00
Last ObjectModification:
2015_12_28-PM-09_25_39
Theory : new!event-ordering
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