Nuprl Lemma : weak-antecedent-conditional
∀es:EO
∀[P1,Q1,P2,Q2:E ⟶ ℙ].
∀dcd_P1:e:E ⟶ Dec(P1 e). ∀f:{e:E| P1 e} ⟶ {e:E| Q1 e} . ∀g:{e:E| P2 e} ⟶ {e:E| Q2 e} .
((Q1 ←==f== P1 ∧ Q2 ←==g== P2) ⇒ λe.((Q1 e) ∨ (Q2 e)) ←==[P1? f : g]== λe.((P1 e) ∨ (P2 e)))
Proof
Definitions occuring in Statement :
weak-antecedent-function: Q ←==f== P,
conditional: [P? f : g],
es-E: E,
event_ordering: EO,
decidable: Dec(P),
uall: ∀[x:A]. B[x],
prop: ℙ,
all: ∀x:A. B[x],
implies: P ⇒ Q,
or: P ∨ Q,
and: P ∧ Q,
set: {x:A| B[x]} ,
apply: f a,
lambda: λx.A[x],
function: x:A ⟶ B[x]
Definitions unfolded in proof :
all: ∀x:A. B[x],
uall: ∀[x:A]. B[x],
implies: P ⇒ Q,
and: P ∧ Q,
member: t ∈ T,
prop: ℙ,
subtype_rel: A ⊆r B,
so_lambda: λ2x.t[x],
so_apply: x[s],
uimplies: b supposing a,
weak-antecedent-function: Q ←==f== P,
cand: A c∧ B,
or: P ∨ Q,
conditional: [P? f : g],
branch: if p:P then A[p] else B fi ,
decidable: Dec(P),
not: ¬A,
false: False,
guard: {T}
Latex:
\mforall{}es:EO
\mforall{}[P1,Q1,P2,Q2:E {}\mrightarrow{} \mBbbP{}].
\mforall{}dcd$_{P1}$:e:E {}\mrightarrow{} Dec(P1 e). \mforall{}f:\{e:E| P1 e\} {}\mrightarrow{} \{e:E| Q1 e\} . \mforall{}g:\{e:E| P2 e\000C\} {}\mrightarrow{} \{e:E| Q2 e\} .
((Q1 \mleftarrow{}==f== P1 \mwedge{} Q2 \mleftarrow{}==g== P2) {}\mRightarrow{} \mlambda{}e.((Q1 e) \mvee{} (Q2 e)) \mleftarrow{}==[P1? f : g]== \mlambda{}e.((P1 e) \mvee{} (P2 e)))
Date html generated:
2016_05_16-AM-10_16_33
Last ObjectModification:
2015_12_28-PM-09_29_05
Theory : new!event-ordering
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