Nuprl Lemma : iterate-rec-dataflow

[S,A,B:Type]. ∀[next:S ⟶ A ⟶ (S × B)]. ∀[L:A List]. ∀[s0:S].
  (rec-dataflow(s0;s,m.next[s;m])*(L) rec-dataflow(rec-dataflow-state(s0;s,m.next[s;m];L);s,m.next[s;m]))


Proof




Definitions occuring in Statement :  iterate-dataflow: P*(inputs) rec-dataflow-state: rec-dataflow-state(s0;s,m.next[s; m];L) rec-dataflow: rec-dataflow(s0;s,m.next[s; m]) list: List uall: [x:A]. B[x] so_apply: x[s1;s2] function: x:A ⟶ B[x] product: x:A × B[x] universe: Type sqequal: t
Definitions unfolded in proof :  rec-dataflow-state: rec-dataflow-state(s0;s,m.next[s; m];L) uall: [x:A]. B[x] member: t ∈ T all: x:A. B[x] nat: implies:  Q false: False ge: i ≥  uimplies: supposing a satisfiable_int_formula: satisfiable_int_formula(fmla) exists: x:A. B[x] not: ¬A top: Top and: P ∧ Q prop: subtype_rel: A ⊆B or: P ∨ Q so_lambda: λ2y.t[x; y] so_apply: x[s1;s2] cons: [a b] colength: colength(L) guard: {T} decidable: Dec(P) nil: [] it: so_lambda: λ2x.t[x] so_apply: x[s] sq_type: SQType(T) less_than: a < b squash: T less_than': less_than'(a;b) pi1: fst(t)

Latex:
\mforall{}[S,A,B:Type].  \mforall{}[next:S  {}\mrightarrow{}  A  {}\mrightarrow{}  (S  \mtimes{}  B)].  \mforall{}[L:A  List].  \mforall{}[s0:S].
    (rec-dataflow(s0;s,m.next[s;m])*(L)  \msim{}  rec-dataflow(rec-dataflow-state(s0;s,m.next[s;m];L);
                                                                                s,m.next[s;m]))



Date html generated: 2016_05_17-AM-10_20_48
Last ObjectModification: 2016_01_18-AM-00_20_35

Theory : process-model


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