Nuprl Lemma : eq_knd_wf
∀[a,b:Knd]. (a = b ∈ 𝔹)
Proof
Definitions occuring in Statement :
eq_knd: a = b,
Knd: Knd,
bool: 𝔹,
uall: ∀[x:A]. B[x],
member: t ∈ T
Lemmas :
Kind-deq_wf,
deq_wf,
Knd_wf
\mforall{}[a,b:Knd]. (a = b \mmember{} \mBbbB{})
Date html generated:
2015_07_17-AM-09_13_03
Last ObjectModification:
2015_01_28-AM-07_55_41
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