Nuprl Lemma : fpf-ap-compose

[x:Top]. ∀[f:a:Top fp-> Top]. ∀[g,eq:Top].  (g f(x) f(x))


Proof




Definitions occuring in Statement :  fpf-compose: f fpf-ap: f(x) fpf: a:A fp-> B[a] uall: [x:A]. B[x] top: Top apply: a sqequal: t
Lemmas :  fpf_ap_compose_lemma top_wf fpf_wf
\mforall{}[x:Top].  \mforall{}[f:a:Top  fp->  Top].  \mforall{}[g,eq:Top].    (g  o  f(x)  \msim{}  g  f(x))



Date html generated: 2015_07_17-AM-11_11_36
Last ObjectModification: 2015_01_28-AM-07_43_00

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