Nuprl Lemma : subtype-fpf
∀[A:Type]. ∀[P:A ─→ ℙ]. ∀[B:A ─→ Type]. (a:{a:A| P[a]} fp-> B[a] ⊆r a:A fp-> B[a])
Proof
Definitions occuring in Statement :
fpf: a:A fp-> B[a],
subtype_rel: A ⊆r B,
uall: ∀[x:A]. B[x],
prop: ℙ,
so_apply: x[s],
set: {x:A| B[x]} ,
function: x:A ─→ B[x],
universe: Type
Lemmas :
subtype-fpf-general
\mforall{}[A:Type]. \mforall{}[P:A {}\mrightarrow{} \mBbbP{}]. \mforall{}[B:A {}\mrightarrow{} Type]. (a:\{a:A| P[a]\} fp-> B[a] \msubseteq{}r a:A fp-> B[a])
Date html generated:
2015_07_17-AM-09_15_26
Last ObjectModification:
2015_01_28-AM-07_52_59
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