{ 
[es:EO]. [P,Q:E 
]. [f:{e:E| P e} E]. (Q 
= f== P 
) }
{ Proof }
Definitions occuring in Statement :
weak-antecedent-surjection: Q = f== P,
es-E: E,
event_ordering: EO,
uall: [x:A]. B[x],
prop: ,
member: t T,
set: {x:A| B[x]} ,
apply: f a,
function: x:A B[x]
Definitions :
uall: [x:A]. B[x],
prop: ,
member: t T,
weak-antecedent-surjection: Q = f== P,
and: P 
Q,
all: x:A. B[x],
exists: 
x:A. B[x]
Lemmas :
weak-antecedent-function_wf,
es-E_wf,
event_ordering_wf
\mforall{}[es:EO]. \mforall{}[P,Q:E {}\mrightarrow{} \mBbbP{}]. \mforall{}[f:\{e:E| P e\} {}\mrightarrow{} E]. (Q \mleftarrow{}\mleftarrow{}= f== P \mmember{} \mBbbP{})
Date html generated:
2011_08_16-AM-11_07_01
Last ObjectModification:
2011_06_18-AM-09_40_22
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