Nuprl Lemma : opposite-side-congruent-diagonals-midpoint

e:BasicGeometry. ∀A,B,C,D,P:Point.
  ((¬Colinear(A;B;C))   AB ≅ CD  BC ≅ DA  Colinear(A;P;C)  Colinear(B;P;D)  {A=P=C ∧ B=P=D})


Proof




Definitions occuring in Statement :  basic-geometry: BasicGeometry geo-midpoint: a=m=b geo-colinear: Colinear(a;b;c) geo-congruent: ab ≅ cd geo-sep: b geo-point: Point guard: {T} all: x:A. B[x] not: ¬A implies:  Q and: P ∧ Q
Definitions unfolded in proof :  all: x:A. B[x] implies:  Q member: t ∈ T basic-geometry: BasicGeometry uall: [x:A]. B[x] subtype_rel: A ⊆B guard: {T} uimplies: supposing a prop: not: ¬A false: False stable: Stable{P} exists: x:A. B[x] and: P ∧ Q geo-cong-tri: Cong3(abc,a'b'c') geo-five-seg-compressed: FSC(a;b;c;d  a';b';c';d') geo-colinear-set: geo-colinear-set(e; L) l_all: (∀x∈L.P[x]) int_seg: {i..j-} lelt: i ≤ j < k decidable: Dec(P) or: P ∨ Q satisfiable_int_formula: satisfiable_int_formula(fmla) select: L[n] cons: [a b] subtract: m cand: c∧ B uiff: uiff(P;Q) iff: ⇐⇒ Q geo-eq: a ≡ b rev_implies:  Q

Latex:
\mforall{}e:BasicGeometry.  \mforall{}A,B,C,D,P:Point.
    ((\mneg{}Colinear(A;B;C))
    {}\mRightarrow{}  B  \#  D
    {}\mRightarrow{}  AB  \mcong{}  CD
    {}\mRightarrow{}  BC  \mcong{}  DA
    {}\mRightarrow{}  Colinear(A;P;C)
    {}\mRightarrow{}  Colinear(B;P;D)
    {}\mRightarrow{}  \{A=P=C  \mwedge{}  B=P=D\})



Date html generated: 2020_05_20-AM-09_57_41
Last ObjectModification: 2020_01_27-PM-10_00_52

Theory : euclidean!plane!geometry


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