Nuprl Rule : axiomEquality

This rule proved as lemma rule_axiom_equality_true3 in file rules/rules_equality4.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ Ax = Ax ∈ (a1 = a2 ∈ A)

  BY axiomEquality ()

  H  ⊢ a1 = a2 ∈ A

Definitions occuring in rule : equal: s = t ∈ T, axiom: Ax

Latex:
H \mvdash{} Ax = Ax BY axiomEquality () H \mvdash{} a1 = a2 Date html generated: 2019_06_20-PM-04_11_45 Last ObjectModification: 2016_07_08-PM-03_49_07 Theory : rules Home Index