Nuprl Rule : axiomSqleEquality

This rule proved as lemma rule_approx_member_eq_true3 in file rules/rules_squiggle6.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ Ax = Ax ∈ (a ≤ b)

  BY axiomSqleEquality ()

  H  ⊢ a ≤ b

Definitions occuring in rule : equal: s = t ∈ T, sqle: s ≤ t, axiom: Ax

Latex:
H \mvdash{} Ax = Ax BY axiomSqleEquality () H \mvdash{} a \mleq{} b Date html generated: 2019_06_20-PM-04_11_56 Last ObjectModification: 2016_07_08-PM-03_49_07 Theory : rules Home Index