Nuprl Rule : axiomSqleEquality
This rule proved as lemma rule_approx_member_eq_true3 in file rules/rules_squiggle6.v
 at https://github.com/vrahli/NuprlInCoq  
H  ⊢ Ax = Ax ∈ (a ≤ b)
  BY axiomSqleEquality ()
  
  H  ⊢ a ≤ b
Definitions occuring in rule : 
equal: s = t ∈ T
, 
sqle: s ≤ t
, 
axiom: Ax
Latex:
H    \mvdash{}  Ax  =  Ax
    BY  axiomSqleEquality  ()
   
    H    \mvdash{}  a  \mleq{}  b
Date html generated:
2019_06_20-PM-04_11_56
Last ObjectModification:
2016_07_08-PM-03_49_07
Theory : rules
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