Nuprl Rule : callbyvalueRemainder

This rule proved as lemma rule_callbyvalue_arith_true in file rules/rules_arith_callbyvalue.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ (a ∈ ℤ) ∧ (b ∈ ℤ) ext <Ax, Ax>

  BY callbyvalueRemainder ()

  H  ⊢ 0 ≤ eval a rem b; 0
  H  ⊢ a ∈ Base
  H  ⊢ b ∈ Base

Definitions occuring in rule : and: P ∧ Q, int: ℤ, pair: <a, b>, sqle: s ≤ t, callbyvalue: callbyvalue, remainder: n rem m, natural_number: $n, member: t ∈ T, base: Base, axiom: Ax

Latex:
H \mvdash{} (a \mmember{} \mBbbZ{}) \mwedge{} (b \mmember{} \mBbbZ{}) ext <Ax, Ax> BY callbyvalueRemainder () H \mvdash{} 0 \mleq{} eval a rem b; 0 H \mvdash{} a \mmember{} Base H \mvdash{} b \mmember{} Base Date html generated: 2019_06_20-PM-04_12_20 Last ObjectModification: 2016_07_08-PM-03_49_02 Theory : rules Home Index