Nuprl Rule : dependentIntersection_memberEquality
This rule proved as lemma rule_free_from_atom_equality_true3 in file rules/rules_free_from_atom.v
at https://github.com/vrahli/NuprlInCoq
H ⊢ b1 = b2 ∈ x:A ⋂ B
BY dependentIntersection_memberEquality ()
H ⊢ b1 = b2 ∈ A
H ⊢ b1 = b2 ∈ B[b1/x]
Definitions occuring in rule :
dep-isect: x:A ⋂ B[x],
equal: s = t ∈ T,
axiom: Ax
Latex:
H \mvdash{} b1 = b2
BY dependentIntersection\_memberEquality ()
H \mvdash{} b1 = b2
H \mvdash{} b1 = b2
Date html generated:
2019_06_20-PM-04_11_56
Last ObjectModification:
2015_11_23-PM-03_41_58
Theory : rules
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