Nuprl Rule : inrEquality
This rule proved as lemma rule_inr_equality_true in file rules/rules_union.v at https://github.com/vrahli/NuprlInCoq
H ⊢ (inr b1 ) = (inr b2 ) ∈ (A + B)
BY inrEquality !parameter{i:l} ()
H ⊢ b1 = b2 ∈ B
H ⊢ A = A ∈ Type
Definitions occuring in rule :
union: left + right,
inr: inr x ,
equal: s = t ∈ T,
universe: Type,
axiom: Ax
Latex:
H \mvdash{} (inr b1 ) = (inr b2 )
BY inrEquality !parameter\{i:l\} ()
H \mvdash{} b1 = b2
H \mvdash{} A = A
Date html generated:
2019_06_20-PM-04_11_54
Last ObjectModification:
2016_07_08-PM-03_48_56
Theory : rules
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