Nuprl Rule : isect_memberEquality

This rule proved as lemma rule_isect_member_equality_true in file rules/rules_isect2.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ b1 = b2 ∈ (⋂x:A. B)

  BY isect_memberEquality !parameter{i:l} z ()

  H z:A ⊢ b1 = b2 ∈ B[z/x]
  H  ⊢ A = A ∈ Type

Definitions occuring in rule : isect: ⋂x:A. B[x], equal: s = t ∈ T, universe: Type, axiom: Ax

Latex:
H \mvdash{} b1 = b2 BY isect\_memberEquality !parameter\{i:l\} z () H z:A \mvdash{} b1 = b2 H \mvdash{} A = A Date html generated: 2019_06_20-PM-04_11_48 Last ObjectModification: 2018_09_25-PM-01_39_43 Theory : rules Home Index